有 2 條數不能計出答案. 請各位幫忙, 要列式的
A) 1 - 2 [3-(x/2 - 1)] = x/4 + 1, 答案 x = 32/3. 請列式
B) 2/7 x a - a = 5, 答案 a = -7 請列式.
中一方程數學
2013-10-18 5:11 am
回答 (3)
2013-10-18 5:21 am
✔ 最佳答案
問題Ａ 1 - 2 [3-(x/2 - 1)] = x/4 + 1
解答Ａ
1 - 2 [3-(x/2 - 1)] = x/4 + 1
1 - [6 - 2(x/2 - 1)] = x/4 + 1
1 - [6 - (x - 2)] = x/4 + 1
1 - (6 - x + 2) = x/4 + 1
1 - (8 - x) = x/4 + 1
1 - 8 + x = x/4 + 1
-7 + x = x/4 + 1
-28 + 4x = x + 4 〔全式乘 4〕
4x = x + 4 + 28
4x = x + 32
3x = 32
x = 32/3
問題Ｂ
2/7 * a - a = 5
解答Ｂ
2/7 * a - a = 5
2*a - 7a = 35 〔全式乘 7〕
-5a = 35
a = 35/(-5)
a = -7
2013-10-18 7:43 am
A)1 - 2 [3-(x/2 - 1)] = x/4 + 1
1 - [6 - 2(x/2 - 1)] = x/4 + 1
1 - [6 - (x - 2)] = x/4 + 1
1 - (6 - x + 2) = x/4 + 1
1 - (8 - x) = x/4 + 1
1 - 8 + x = x/4 + 1
-7 + x = x/4 + 1
-28 + 4x = x + 4
4x = x + 4 + 28
4x = x + 32
3x = 32
x = 32/3
B)2/7 * a - a = 5
2*a - 7a = 35
-5a = 35
a = 35/(-5)
a = -7
1 - [6 - 2(x/2 - 1)] = x/4 + 1
1 - [6 - (x - 2)] = x/4 + 1
1 - (6 - x + 2) = x/4 + 1
1 - (8 - x) = x/4 + 1
1 - 8 + x = x/4 + 1
-7 + x = x/4 + 1
-28 + 4x = x + 4
4x = x + 4 + 28
4x = x + 32
3x = 32
x = 32/3
B)2/7 * a - a = 5
2*a - 7a = 35
-5a = 35
a = 35/(-5)
a = -7
2013-10-18 6:13 am
A) 1 - 2 [3-(x/2 - 1)] = x/4 + 1
- 2 [3 - x/2 + 1] = x/4
- 6 + x - 2 = x/4
- 24 + 4x - 8 = x
3x = 32
x = 32/3
B) 2/7 x a - a = 5
a (2/7 - 1) = 5
a = - (5 x 7/5)
a = - 35/7
a = - 5
- 2 [3 - x/2 + 1] = x/4
- 6 + x - 2 = x/4
- 24 + 4x - 8 = x
3x = 32
x = 32/3
B) 2/7 x a - a = 5
a (2/7 - 1) = 5
a = - (5 x 7/5)
a = - 35/7
a = - 5
收錄日期: 2021-04-13 19:46:24
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