物理力學運動學問題

Let d be the distance travelled by the truck before collision occurs.
Hence, d = 5t
where t is the time lapsed before collision

Consider So's car, use equation: s = ut + (1/2)at^2
with s = 155 + d, u = 30 m/s, a = -2 m/s^2,
hence, 155 + d = 30t + (1/2).(-2)t^2
155 + 5t = 30t -t^2
t^2 - 25t + 155 = 0
t = 11.38 s or 13.62 s (rejected)

Therefore, collision occurs at 11.38 s after So's car enters into the tunnel.

Distance travelled by So's car = (155 + 5 x 11.38) m = 212 m

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