PHYSICS(MECHANICS)
2013-10-16 10:57 pm
A 2000 kg race car make a 90 degree turn on a track, as shown in the following figure.
Its speed is 0.50 m/s before the turn and 0.40 m/s after the turn. Using the
coordinate system specified in the figure, calculate the change in the linear
momentum of the car due to the turn.
回答 (2)
2013-10-17 3:26 am
✔ 最佳答案
Momentum is a vector quantity. You need to use vector substraction in calculating the change of linear momentum.Since change of momentum = final momentum - initial momentum
the momentum vectors thus forms a right-angle triangle with the hypotenus as the "momentum difference".
Thus, change of momentum = square-root[(2000x0.5)^2 + (2000x0.4)^2] kg.m/s
= 1281 kg.m/s
Let a be angle between the momentum change and the final momentum
hence, tan(a) = 0.5/0.4
a = 51.34 degrees.
2013-10-17 12:11 am
我都中大ga，LOL.
收錄日期: 2021-04-20 14:24:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131016000051KK00096