Form a quadratic equation with roots 2α – 3 and 2β - 3.
更新1:
still do not understand.
更新2:
thanks, I have already understood.
F.4 Math
2013-10-07 7:37 pm
Suppose α and β are the roots of the equation x2 + 6x - 2= 0.
Form a quadratic equation with roots 2α – 3 and 2β - 3.
Form a quadratic equation with roots 2α – 3 and 2β - 3.
回答 (1)
2013-10-07 8:20 pm
✔ 最佳答案
由原方程 x² + 6x - 2= 0 ; 得 α + β = -6 ; αβ = -2設所要求的方程為 X² + hX + k = 0
sum of roots ==> 2α – 3 + 2β - 3 = 2(α+β) - 6 = -h
product of root = (2α – 3)(2β - 3) = k
.......
2013-10-07 21:06:11 補充：
Sorry,睇唔到你的補充，但當睇到時你已經OK了，恭喜、恭喜。
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131007000051KK00052