F.4 Math

👨🏻‍🏫 學術台數學

[匿名]

2013-10-07 7:37 pm

Suppose α and β are the roots of the equation x2 + 6x - 2= 0.
Form a quadratic equation with roots 2α – 3 and 2β - 3.

更新1:

still do not understand.

更新2:

thanks, I have already understood.

回答 (1)

用戶4366

2013-10-07 8:20 pm

✔ 最佳答案

由原方程 x² + 6x - 2= 0 ; 得 α + β = -6 ; αβ = -2

設所要求的方程為 X² + hX + k = 0

sum of roots ==> 2α – 3 + 2β - 3 = 2(α+β) - 6 = -h

product of root = (2α – 3)(2β - 3) = k

.......

2013-10-07 21:06:11 補充：
Sorry,睇唔到你的補充，但當睇到時你已經OK了，恭喜、恭喜。

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