更新1:
Thanks , Mr KWOK, up to your advice, i know how to do,
f.4 maths
2013-10-06 7:59 pm
22. If α and α + 1 are the roots of the equation 4x2 + 4kx + (5k + 13) = 0, find the possible value(s) of k.
回答 (1)
2013-10-06 8:17 pm
✔ 最佳答案
Sum of roots :α + (α + 1) = -(4k/4) [ -b/a ]
2α+1 = -k .............. (h)
product of roots (α)(α + 1)= (5k + 13)/4 [ c/a ]
4α² + 4α = 5k + 13 ............ (q)
from (h) 2α+1 = -k
k = -2α-1
Sub into (q) :
4α² + 4α = 5k + 13
4α² + 4α = 5(-2α-1) +13
自己再做啦！
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20131006000051KK00080