rate, ratio and proportion

2013-10-01 4:33 am
Find the vlaues of a if a= x/(2y+4z) = 2y/(x+4z) = 4z/(x+2y)
there are 2 values

回答 (2)

2013-10-01 12:21 pm
✔ 最佳答案
a = x/(2y+4z) = 2y/(x+4z) = 4z/(x+2y)∴ a(2y+4z) = x , a(x+4z) = 2y , a(x+2y) = 4z

a(2y+4z) + a(x+4z) + a(x+2y) = x + 2y + 4z
a(2x + 4y + 8z) = x + 2y + 4z
2a(x + 2y + 4z) = x + 2y + 4z
(2a - 1) (x + 2y + 4z) = 0
2a - 1 = 0 or x + 2y + 4z = 0
If 2a - 1 = 0 then a = 1/2 ,
or
if x + 2y + 4z = 0 , then x = - 2y - 4z , 2y = - x - 4z , 4z = - x - 2y ,
hence a = - 1 .
2013-10-01 3:28 pm
謝謝你的教導呀~
彩虹~


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