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圖片參考:
http://imgcld.yimg.com/8/n/HA05107138/o/20131006104222.jpg
2013-10-07 20:21:54 補充:
1. Thank you for advising the Euler equation method. But apparently this does not work. Should the question specifies the boundary values, i.e. f(0) and f(1) instead of the initial values f(0) and f'(0) in order to use this method?
2. I have not confused (r,θ) with (x,y).
2013-10-07 20:27:00 補充:
By using Euler equation and the initial values, I can get f(x) = 1/(cos x + sin x) which corresponds to a straight line in my polar coordinates equivalence r(θ) = 1/ (cos θ + sin θ). The integral yields 2 sin (1/2) = 0.9589..
But consider f(x) = 1 - x +x^2/2 the integral = 0.8495 smaller than above
2013-10-07 20:28:59 補充:
My piecewise smooth curve gives even a smaller value of sin(1)=0.8415
2013-10-08 20:38:52 補充:
I think Euler equation requires the 2 boundary conditions f(0) and f(1) to get the correct result. Let's say if we specify f(0)=1 and f(1) = 1, we will get f(x) = 1/(cos x + (1 - cos 1)/sin 1 * sin x) and the integral becomes 2 sin (1/2) = 0.9589 (which I mistakenly copied as the result for
2013-10-08 20:41:40 補充:
f(x) = 1/(cos x + sin x)
This 2 sin (1/2) agrees with the length of straight line from (r,θ) = (1,0) t0 (1,1).
I have tried different values of f(1) and the result is always correct.
Likewise for the integral sort(1+f'(x)^2) we get the same conclusion.