the integral P(f)=∫_[0~1] [xf²(x)-x²f(x)] dx and evaluate P(f).
更新1:
Just a simple problem, do not scare yourself.
Just a simple problem, do not scare yourself.
收錄日期: 2021-04-23 23:25:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130930000051KK00006