中二問題 因式分解 10分!急!

1) a^4+4b^4
=a^4+4a^2b^2+4b^4－4a^2b^2
=(a^2+2b^2)^2－(2ab)^2
=(a^2－2ab+2b^2)(a^2+2ab+2b^2)

2) (t^2+4t+4)－9u^2
=(t+2)^2－(3u)^2
=(t－3u+2)(t+3u+2)

3) a^2－6ab+9b2
=a^2－2*a*(3b)+(3b)^2
=(a－3b)^2

1) a^4-4b^4 (您係唔係打錯做＋?因＋係無得做落去...)

= (a²)²-(2b²)²

= (a²+2b²)(a²-2b²)


2) (t²+4t+4)-9u²

= (t+2)²-9u²

= [(t+2)+3u][(t+2)-3u]

= (t+2+3u)(t+2-3u)


3) a²-6ab+9b² (您係唔係打少個 ^ ?)

= (a)²-2(a)(3b)+(3b)²

= (a-3b)²

2.(t^2+4t+4)-9u^2

=﹝t^2+2(t)(2)+2^2﹞-9u^2
=(t+2)^2-9u^2
=(t+20)^2-(3w)^2
=(t+2-3w)(t+2+3u)

3. a^2-6ab+9b2

=a^2-2(a)(3b)+(3b)^2
=(a-3b)^2

希望可以幫到你!