1) a^4+4b^4
2) (t^2+4t+4)-9u^2
3) a^2-6ab+9b2
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中二問題 因式分解 10分!急!
2013-09-27 4:53 am
回答 (3)
2013-09-27 3:52 pm
✔ 最佳答案
1) a^4+4b^4=a^4+4a^2b^2+4b^4－4a^2b^2
=(a^2+2b^2)^2－(2ab)^2
=(a^2－2ab+2b^2)(a^2+2ab+2b^2)
2) (t^2+4t+4)－9u^2
=(t+2)^2－(3u)^2
=(t－3u+2)(t+3u+2)
3) a^2－6ab+9b2
=a^2－2*a*(3b)+(3b)^2
=(a－3b)^2
2013-09-28 8:29 pm
1) a^4-4b^4 (您係唔係打錯做＋?因＋係無得做落去...)
= (a²)²-(2b²)²
= (a²+2b²)(a²-2b²)
2) (t²+4t+4)-9u²
= (t+2)²-9u²
= [(t+2)+3u][(t+2)-3u]
= (t+2+3u)(t+2-3u)
3) a²-6ab+9b² (您係唔係打少個 ^ ?)
= (a)²-2(a)(3b)+(3b)²
= (a-3b)²
= (a²)²-(2b²)²
= (a²+2b²)(a²-2b²)
2) (t²+4t+4)-9u²
= (t+2)²-9u²
= [(t+2)+3u][(t+2)-3u]
= (t+2+3u)(t+2-3u)
3) a²-6ab+9b² (您係唔係打少個 ^ ?)
= (a)²-2(a)(3b)+(3b)²
= (a-3b)²
2013-09-27 6:38 am
2.(t^2+4t+4)-9u^2
=﹝t^2+2(t)(2)+2^2﹞-9u^2
=(t+2)^2-9u^2
=(t+20)^2-(3w)^2
=(t+2-3w)(t+2+3u)
3. a^2-6ab+9b2
=a^2-2(a)(3b)+(3b)^2
=(a-3b)^2
希望可以幫到你!
=﹝t^2+2(t)(2)+2^2﹞-9u^2
=(t+2)^2-9u^2
=(t+20)^2-(3w)^2
=(t+2-3w)(t+2+3u)
3. a^2-6ab+9b2
=a^2-2(a)(3b)+(3b)^2
=(a-3b)^2
希望可以幫到你!
收錄日期: 2021-04-13 19:44:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130926000051KK00218