x₁- 2x₂+ 3x₃= 4Let x₁- 2x₂= k , then x₁= x₂= - k is a solution set.
So x₁and x₂can be written as x₁= 2m - k , x₂= m - k.
(where m is a parametric)k + 3x₃= 4 , then k = x₃= 1 is a solution set.
So k and x₃can be written as k = 1 - 3n , x₃= 1 + n.
(where n is a parametric) ∴ The required parametric equation is
x₁= 2m - k = 2m - (1 - 3n) = 2m + 3n - 1
x₂= m - k = m - (1 - 3n) = m + 3n - 1
x₃= n + 1