急! More about Dispersion 13Q5

2013-09-17 3:27 am
請詳細步驟教我計下條 :


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回答 (1)

2013-09-17 9:40 am
✔ 最佳答案

圖片參考:http://faculty.virginia.edu/PullenLab/WJIIIDRBModule/standard%20normal%20distribution.jpg


(a) The required percentage (based on the approximation mentioned in the textbook) is
100% - (100% - 99.7%)/2
= 100% - (0.3%)/2
= 100% - 0.15%
= 99.85%.

(b) The number of candidates with scores higher than Wilson is 20000*99.85% = 19970.


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