Maths Differentiation 20點!!

2013-09-16 9:22 am
1. a) Given that x = cos y

i) find dy/dx in terms of y (by differentiating both sides with respect to x)
ii) find dy/dx in terms of x (using the fact that (cos y)^2 +(sin y)^2 = 1)

b) Use part a to find dy/dx in terms of x when y = cos^(-1) x


2. a) Given that x = tan y,

i) find dy/dx in terms of y (by differentiating both sides with respect to x)
ii) find dy/dx in terms of x (using the fact that 1 + (tan y)^2 = (sec y)^2 )

b) b) Use part a to find dy/dx in terms of x when y = tan^(-1) x.
更新1:

One more question to go... 3. A population of flies P is given by the formula P = A e^( - kt ), where t is the time in days measured from a time when P = 2000 a) Write down th vlue of A b) Given that P = 500 whwen t = 5, show that k = (1/5) ln 4, c) Fine th value of P when t = 8 days.

更新2:

Correction!! 3a) Write down the value of A

回答 (2)

2013-09-16 4:45 pm
✔ 最佳答案
(1)(ai)

x = cos y
1 = - sin y (dy/dx)
dy/dx = - cosec y

(1)(aii)

dy/dx
= - cosec y
= - 1 / sin y
= - 1 / [1 - (cos y)^2]^(1/2)
= - 1 / (1 - x^2)^(1/2)

(1)(b)

y = cos^(-1) x
x = cos y
dy/dx = - 1 / (1 - x^2)^(1/2)


(2)(ai)

x = tan y
1 = (sec y)^2 (dy/dx)
dy/dx = (cos y)^2

(1)(aii)

dy/dx
= (cos y)^2
= 1 / (sec y)^2
= 1 / [1 + (tan y)^2]
= 1 / (1 + x^2)

(1)(b)

y = tan^(-1) x
x = tan y
dy/dx = 1 / (1 + x^2)
參考: knowledge
2013-09-19 9:52 pm
3. A population of flies P is given by the formula P = A e^( - kt ), where t is the time in days measured from a time when P = 2000

a) Write down the value of A.
b) Given that P = 500 when t = 5, show that k = (1/5) ln 4,
c) Fine the value of P when t = 8 days.

2013-09-19 13:55:56 補充:
a) When t = 0, P = A = 2000

b) 500 = 2000 e^(-k*5)
1/4 = e^(-k*5)
-5k = ln(1/4) = ln(4^(-1)) = -ln4
5k = ln4
k = (1/5)ln4

c) P = 2000 e^(-(1/5)ln4 * 8)
= 2000 e^( -(8/5)ln4 )
= 2000 e^( ln4^(-8/5) )
= 2000*4^(-8/5)
= 217.6376408


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