F.2 Maths Factorization

2013-09-06 8:46 pm
1. m^ 4- 18m^ 2+ 81
2. 16p^ 4- 8p^ 2q^2+ q^4

回答 (2)

2013-09-06 9:10 pm
✔ 最佳答案
1. m^ 4- 18m^ 2+ 81
[m^2]^2 - 18(m^ 2) + 81
(m^2 - 9)((m^2 - 9)
(m +3)(m - 3)(m +3)(m - 3)
(m +3)^2 (m - 3)^2

2. 16p^ 4- 8p^ 2q^2+ q^4
16(p^ 2)^2 - 8(pq)^2+ (q^2)^2
(4p^2 - q^2)(4p^2 - q^2)
((2p)^2 - q^2)((2p)^2 - q^2)
(2p +q)(2p - q)(2p +q)(2p - q)
(2p +q)^2 (2p - q)^2
2013-09-06 9:17 pm
m^4 = (m^2)^2

m^ 4- 18m^ 2+ 81
= (m^2)^2 - 2.9.m^2 + 9^2
= (m^2 - 9)^2

or let A = m^2

then
m^ 4- 18m^ 2+ 81
= A^2 - 2.9.A + 9^2
= (A - 9)^2
= (m^2 - 9)^2

Similar
16p^ 4- 8p^2q^2+ q^4
= (4p^ 2)^2 - 2.4p^ 2.q^2 + (q^2)^2
= (4p^ 2 - q^2)^2

2013-09-06 13:22:31 補充:
a^2 - b^2 = (a+b)(a-b)

m^2 - 9 = (m^2 - 3^2) = (m+3)(m-3)

=>
m^ 4- 18m^ 2+ 81
= (m^2 - 9)^2
= [(m+3)(m-3)]^2
= (m+3)^2(m-3)^2


4p^ 2 - q^2 = (2p)^2 - q^2 = (2p + q)(2p - q)

=>
16p^ 4- 8p^2q^2+ q^4
= (2p + q)^2.(2p - q)^2

2013-09-07 02:09:18 補充:
https://www.dropbox.com/s/1bpt9fyqj2kp5sn/20130906PIC02.png


收錄日期: 2021-04-11 20:02:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130906000051KK00062

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