F.2 Maths Factorization

[匿名]

2013-09-06 7:29 pm

Factorize the following polynimials by groupin terms.
1.p(pq+2q^2+3q-1)-(2q+3)
2.Factorize 9(a-2b)^2-6n(2b-a).
Hence factorize 3am-6bm+9(a-2b)^2-6n(2b-a)

回答 (1)

Godfrey

2013-09-06 8:57 pm

✔ 最佳答案

1. p(pq+2q^2+3q-1)-(2q+3)
p^2q+2pq^2+3pq -p-2q-3)
p^2q+2pq^2+3pq –(p+2q+3)
pq(p+2q+3) –(p+2q+3)
pq(p+2q+3) (pq –1)

2.Factorize 9(a-2b)^2-6n(2b-a).
9(a-2b)^2+6n(a – 2b)
. (a – 2b)(9(a- 2b) + 6n)
(a – 2b)(9a- 18b + 6n)
3(a – 2b)(3a - 6b + 2n)

Hence factorize 3am-6bm +9(a-2b)^2-6n(2b-a)
3m(a-2b) +9(a-2b)^2-6n(2b-a)
3m(a-2b) +3(a – 2b)(3a - 6b + 2n)
3(a - 2b) (m +(3a - 6b + 2n)
3(a - 2b) (3a - 6b + m + 2n)

2013-09-06 12:58:59 補充：
Correction:
1. p(pq+2q^2+3q-1)-(2q+3)
p^2q+2pq^2+3pq -p-2q-3)
p^2q+2pq^2+3pq –(p+2q+3)
pq(p+2q+3) –(p+2q+3)
(p+2q+3) (pq –1) ANSWER

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