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Question
Solve 5(x-4) =3(x+3)-1.
Hence, solve 5(3y-2) = 3(3y+5)-1.
Solution
5(x-4) = 3(x+3)-1
5x - 20 = 3x + 9 -1
2x = 28
x = 14
For solving 5(3y-2) = 3(3y+5)-1,
consider letting x-4 = 3y-2, then x+3 = 3y-2+7 = 3y+5.
Make use of the previous result,
x = 14
That is, 3y - 2 = x - 4 = 14 - 4 = 10
3y = 12
y = 4
2013-08-29 21:21:09 補充:
此題目有點像昨晚已經見過的。
是否 皎潔明月 已經回答過一次?
但尋不回~
2013-08-29 21:29:42 補充:
噢~
可能是:
http://hk.knowledge.yahoo.com/question/question?qid=7013082800381
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7013082800381