1. rs=3(r+t) 〔r〕
2. a=b+2 〔b〕
3. 1+3p=q(p+7) 〔p〕
S.2 Change Subject
2013-08-27 8:34 pm
回答 (1)
2013-08-27 8:52 pm
✔ 最佳答案
1.rs = 3(r + t) (r)
rs = 3r + 3t
rs - 3r = 3t
r(s - 3) = 3t
r = 3t / (s - 3)
2.
a = b + 2 (b)
a - b = 2
-b = 2 - a
b = -2 + a
3.
1 + 3p = q(p + 7) (p)
1 + 3p = pq + 7q
3p - pq = 7q - 1
p(3 - q) = 7q - 1
p = (7q - 1) / (3 - q)
2013-08-27 12:55:53 補充：
第 2 題要小心正負號。
-b = 2 - a 會變成 b = -2 + a。
收錄日期: 2021-04-13 19:41:42
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130827000051KK00091