數學運算式子問題

2013-08-14 8:46 am
http://imageshack.us/a/img534/5435/gp6a.jpg

關於數學運算問題,想問一下第一行式子怎麼化簡成第二行式子的

知道的請告知,感謝~

回答 (2)

2013-08-14 9:03 am
✔ 最佳答案
xy2(y2 - y1) + (1/2)x(y1² - y2²)

= -xy2(y1 - y2) + (1/2)x(y1² - y2²)

= -(1/2)•2xy2(y1 - y2) + (1/2)x(y1 +y2)(y1 - y2)

= (1/2)x(y1 - y2) [-2y2 + (y1 + y2)]

= (1/2)x(y1 - y2) [y1 - y2]

= (1/2)x(y1 - y2)²
參考: andrew
2013-08-14 9:07 am
噢~
我遲了~

請看:
http://imgcld.yimg.com/8/n/HA00430218/o/20130814010625.jpg

:)


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