求數學答案(中二)

1. 6t^2-2t = 2t(3t-1)

2. 6ab-18a^2b+12ab^2 = 6ab(1-3a+2b)

3. ab-c^2d+ac^2-bd = ab+ac^2-bd-c^2d = a(b+c^2)-d(b+c^2) = (a-d)(b+c^2)

4. -p(r-s)-5(s-r) = -p(r-s)+5(r-s) = (-p+5)(r-s) = (p-5)(s-r)

5. 25a^2-4b^2 = (5a)^2 - (2b)^2 = (5a+2b)(5a-2b)

6. m^2-16mn+64n^2 = m^2 - 2(m)(8n) + (8n)^2 = (m-8n)^2

7. x^2+3x-10 = (x+5)(x-2)

8. 8x^2x-3 打錯題目了，你更正後我再答。

我幫你試三個cases：
8x^2 - 2x - 3 = (2x+1)(4x-3)
8x^2 - 10x - 3 = (2x-3)(4x+1)
8x^2 + 5x - 3 = (8x-3)(x+1)


2013-08-17 15:49:01 補充：
菲娜，要努力呀！

1. (c^6)^-8 = c^(-48) = 1/c^48

2. (5a^(-3) b)^2 = 5^2 a^(-6) b^2 = 25b^2/a^6

3. (ab^(-3)/5b^(-2))^4 = (a/5b)^4 = a^4/(625b^4)

1. 6t^2-2t = 2t(3t-1)

2. 6ab-18a^2b+12ab^2 = 6ab(1-3a+2b)

3. ab-c^2d+ac^2-bd = ab+ac^2-bd-c^2d = a(b+c^2)-d(b+c^2) = (a-d)(b+c^2)

4. -p(r-s)-5(s-r) = -p(r-s)+5(r-s) = (-p+5)(r-s) = (p-5)(s-r)

5. 25a^2-4b^2 = (5a)^2 - (2b)^2 = (5a+2b)(5a-2b)

6. m^2-16mn+64n^2 = m^2 - 2(m)(8n) + (8n)^2 = (m-8n)^2

7. x^2+3x-10 = (x+5)(x-2)

8. 8x^2x-3 打錯題目了

1. 6t^2-2t
= 2t(3t-1)

2. 6ab-18a^2b+12ab^2
= (1-3a+2b) 6ab


3. ab-c^2d+ac^2-bd
= a(b+c^2)-d(b+c^2)
= (b+c^2)(a-d)

4. -p(r-s)-5(s-r) =
-p(r-s)+5(r-s)
= (s-r)(p-5)

5. 25a^2-4b^2
= (5a)^2 - (2b)^2 1. 6t^2-2t = 2t(3t-1)
= (5a-2b)(5a+2b)

6. m^2-16mn+64n^2
= m^2 - 2(m)(8n) + (8n)^2
= (m-8n)^2

7. x^2+3x-10
= (x-2)(x+5)

2013-08-13 22:48:24 補充：
For number 8,I think the answer is undetermined because I cannot calculate!!! >-<

Hope U understand all the steps,welcome writing a letter to me!!! :)