p.6-f.1方程數學題一問

2013-08-12 9:40 pm
2(x- 2x-3/4) = -1/6 + 2x
2乘以開括號x減4分之2x減3等於6分之-1加2x
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回答 (3)

2013-08-12 9:57 pm
✔ 最佳答案
2(x- (2x-3)/4) = -1/6 + 2x
2x-(4x-6)/4 = -1/6 + 2x
(-4x+6)/4 = -1/6
-4x+6 = -2/3
-4x = -20/3
x= 5/3
2013-08-13 8:46 pm
I am not so sure which case are you saying:

Case1:

2[x-2x-(3/4)] = (-1/6) + 2x

2[-x-(3/4)]-2x=(-1/6)

-2x-(3/2)-2x=(-1/6)

-4x=(-1/6)+(3/2)

-4x=(4/3)

x=-(1/3)

Case2:

2{x-[(2x-3)/4]}=(-1/6)+2x

x-[(2x-3)/4]=[(-1/6)+2x]/2

(-2x+3)/4=[(-1/12)+x]-x

-2x+3=4(-1/12)

-2x=(-1/3)-3

x=(-10/3)/-2

x=10/6

x=5/3

But I think you are asking the second one!
參考: me
2013-08-12 10:53 pm
2(x-2x-3/4)=-1/6+2x
2x-4x-6/4=-1/6+2x
2x-4x-2x=-1/6+6/4
-4x=16/12
-48x=16
-x=16/48
-x=1/3
x=1/3


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