✔ 最佳答案
Let $a and $s be the amount of money Alan and Scott owned respectively
0.9(a+s)=a..............(1)
0.85(a+s)=a-16.......(2)
From (1),
0.9(a+s)=a
0.9a+0.9s=a
0.9s=0.1a
a=9s........................(3)
Sub. (3) into (2),
0.85(a+s)=a-16
0.85(9s+s)=9s-16
8.5s=9s-16
16=0.5s
s=32
Sub. s=32 into (3)
a=9s
a=9(32)
a=288
Therefore, Alan and Scott have $288 and $32
The sum of the money = $(288+32)=$320
2013-07-30 20:56:52 補充:
Some steps can be omitted. I just want you to understand the calculation easily.
2013-07-30 20:57:29 補充:
Correction:
Therefore, Alan and Scott have $288 and $32 respectively.
2013-07-31 22:37:34 補充:
Alan擁有的錢為$a
Scott擁有的錢為$s
2人共有$(a+s)
Alan佔整體的90%
所以a=(a+s)x90%
a=0.9(a+s)...(1)
當Alan給Scott$16的時候
Alan的錢就會變成$(a-16)
而他有的錢會變成整體的85%
整體的錢是不變的
所以a-16=(a+s)x85%
a-16=0.85(a+s)...(2)
明白了嗎??