晚安 打擾了 這題"波" 的問題 怎麼解才行!?

In the displacement-distance diagram (y vis x), the wave is travelling towards the right.
Hence, the crest on the left of point a will move towards a, thus a is moving upward.
For b, the equilibrium position to the left of b will move towards it, thus b is moving upward.
For c, the trough to the left of c will move towards it, thus c is moving downward.
For d, the equilibrium position to the left of d will move towards it, thus d is moving downward.
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In the given displacement-time graph (y vis t), points on the left represent earlier time, whereas thos on the right represent later time.

For point e, it has just passed a crest (i.e. the one on the left), and is moving towards the equilibrium position (i.e. the one on its right). Thus point e is moving downward.

For point f, it has just passed an equilibrium position (i.e. the one on the left), and is moving towards a trough (i.e. the one on its right). Thus point f is moving downward.

For point g, it has just passed a trough (i.e. the one on the left), and an equilibrium position is coming ( (i.e. the one on its right). Thus point e is moving upward.

For point h, it has just passed an equilibrium position (i.e. the one on the left), and a crest is coming (i.e. the one on the right). Thus point h is moving upward.

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2013-07-30 02:35:07 補充：
Bi Chan Wai Yip Answer " BO + BO + BO "
Bi BOBA 2014.07.01

入門做法

1)在原圖上畫一個比原圖的時間(x-axis)差很少(即是將原圖向右移動後的圖像)。

2)在指定的地方比較原圖及新圖的分別。

3)決定那點是向上、向下或保持不動。

a)
a:向上
b:向上
c:向下
d:向下

b)
e:向上
f:向上
g:向下
h:向下

2013-07-29 22:15:58 補充：
*在原圖上畫一個比原圖的時間(x-axis)差很少的波

2013-07-29 22:54:32 補充：
你對!

是你書的答案

我讀英文PHYSICS的，不太懂中文

b的是問位移(displacement)
這個你只要看那點的前方是高過它還是低過它就行了