Jacky mixes 250mL of solution A with 750mL of solution B. Solution A and solution B contain 22% and 6% of alcohol respectively. What is the percentage of alcohol in mixture?
F.2 Percentages
2013-07-20 9:44 pm
回答 (1)
2013-07-20 9:54 pm
✔ 最佳答案
Alcohol in solution A=250x22%=55mL Alcohol in solution B=750x6%=45mL
The percentage of alcohol in mixture
=[55+45)/(250+750)]x100%
=(100/1000)x100%
=10%
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收錄日期: 2021-04-13 19:34:41
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