220.0 cm3 of water are added to 10.5mol dm–3 hydrochloric acid so that the new molarity of the solution is 1.26mol dm–3
. What is the volume of the original acid used?
A 18.3 cm3
B 25.0 cm3
C 26.4 cm3
D 30.0 cm3
. 420.0 cm3 of water are added to 30.0 cm3 of sodium hydroxide solution so that the new
molarity of he solution is 0.210 mol dm–3
.
What is the molarity of the original solution?
A 2.94mol dm–3
B 3.15mol dm–3
C 6.00mol dm–3
D 6.43mol dm–3