The value of delta H degrees for the reaction below is -126 kJ
2Na2O2 (s) + 2H2O (i) -----> 4NaOH (s) + O2 (g)
Can you please show me how to get this?
The amount of heat that is released by the reaction of 25.0 g of Na2O2 with water is in kJ?
2013-06-21 11:44 pm
回答 (1)
2013-06-22 10:23 pm
✔ 最佳答案
(25.0 g Na2O2) / (77.97840 g Na2O2/mol) x ( -126 kJ / 2 mol Na2O2) = -20.2 kJ
收錄日期: 2021-04-30 13:26:44
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130621154414AAzBewN