MATH HELP [PIC INCLUDED]?

2013-06-19 9:49 am
http://tinypic.com/r/kdx44y/5
I think this is the same with f(x). I'm not sure. Still, i don't know how to do this.
Thanks in advance!

回答 (6)

2013-06-19 9:58 am
✔ 最佳答案
Its very simple. First draw a line touching all the points in the graph.

G(t) is given as -3 right. So go down the y-axis till you reach -3. Draw a horizontal line through -3 and see where it touches the given graph. You'll find that it touches the graph at -5. Which means that the answer is t = -5
2013-06-19 9:53 am
The function has gradient 1 and passes through (0, 2)

=> g(t) = t + 2

so, if g(t) = -3

then, t + 2 = -3

=> t = -5

So, when t = -5, g(t) = -3

:)>
2016-11-10 3:15 pm
The trend would properly be defined as: 5n + a million = S the place "n" equals to the form variety and "S" equals the great of toothpicks. we are in a position to rearrange it to: (S - a million)/5 = n we are able to then get: (one hundred and one - a million)/5 = n 20 = n the respond is 20 Edit: it is so ordinary because it fairly is.
2013-06-19 9:58 am
g(t) is the y value
so when is the x value (t) at -3?
look at the chart....it happens when y is -1
2013-06-19 9:56 am
Well for f(X) it equals 0
參考: I can't view the picture so ya but just rEply and tell me what it is I will give you the answer.
2013-06-19 9:54 am
Question: Given the graph of y = g(t) below, determine the value of t for which g(t) = -3. Answer as an integer.

So yeah, this is the same as just f(x). g(t) is just another way of saying it, but the notation means the same thing.

In this case, the t values are the x values and the g(t) values are the y values. It makes things a lot easier to think of it like that. They're telling you that the y value (g(t)) is -3 and you need to find the x value (t) at that point. So if you go down the y-axis (the vertical one) to negative three you'll see that there's a point. Go across to that point. The coordinates are (-5, -3). This tells you that the x value (t) is -5 at the point. So your answer:
t = -5

Hope this helps! :)


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