✔ 最佳答案
You could still use W = (1/2)kx^2 if you wish, but the calculation is a bit complicated.
When the driver sits on the taptap, the springs are compressed and oscillate in simple harmonic motion. When the motion dies down, the kinetic energy of oscillation has changed into heat, leaving only the potential energy which is transferred to the energy possessed by the spring.
Hence, only half of the original (gravitational) potential energy of the driver remains (the other half, as explained above, vanishes when the oscillation dies down), which is = (70g x 2.5x10^-2)/2 J = 8.75 J
[Take g = 10 m/s^2]
Therefore, 8.75 = (1/2)k(2.5x10^-2)
k = 2 x 8.75/(2.5x10^-2)^2 N/m = 28 000 N/m
You get the same result on using F = kx
Anyway, the use of F = kx is much simpler.