chemistry~~!!~~

I think you are asking redox reaction of nitric acid.

I study Chemistry in English so I try my best to explain in an easy way.

For very dilute nitric acid,

2X(s)+2HNO3(aq)--->2XNO3(aq)+H2(g)

Y(s)+2HNO3(aq)--->Y(NO3)2(aq)+H2(g)

2Z(s)+6HNO3(aq)--->2Z(NO3)3(aq)+3H2(g)

For metal located below lead (copper or below), no reaction occurs.

For dilute nitric acid,

X(s) + 2HNO3(aq)--->XNO3(aq)+2NO(g)+H2O(l)

3Y(s) + 8HNO3(aq)--->3Y(NO3)2(aq)+2NO(g)+4H2O(l)

Z(s) + 4HNO3(aq)--->Z(NO3)3(aq)+NO(g)+2H2O(l)

Dilute nitric acid react with copper

NO will further react with O2 to give NO2

2NO(g)+O2(g)--->2NO2(g)

For concentrated nitric acid,

X(s) + 2HNO3(aq)--->XNO3(aq)+NO2(g)+H2O(l)

Y(s) + 4HNO3(aq)--->Y(NO3)2(aq)+2NO2(g)+2H2O(l)

Z(s) + 6HNO3(aq)--->Z(NO3)3(aq)+3NO2(g)+3H2O(l)

Concentrated nitric acid cannot react with gold and platinum

X=metal which will give out 1 e- in its half equation
Y=metal which will give out 2 e- in its half equation
Z=metal which will give out 3 e- in its half equation

我淨係知metal+acid→hydrogen
有咩唔同我就唔知啦
E.G. Nitric acid+Magnesium/zinc→hydrogen