積分怎麼積

2013-06-17 4:30 pm
∫cot(x)csc^2(x)dx=??

回答 (1)

2013-06-17 4:45 pm
✔ 最佳答案
method I

∫ cot x (csc x)^2 dx
= - ∫ csc x d(csc x)
= - (1/2) (csc x)^2 + C, where C is a constant

method II

Let u = csc x
du = - csc x cot x dx

∫ cot x (csc x)^2 dx
= - ∫ csc x (- csc x cot x dx)
= - ∫ u du
= - (1/2) u^2 + C
= - (1/2) (csc x)^2 + C, where C is a constant
參考: knowledge


收錄日期: 2021-04-28 14:22:48
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