6.7cm3 of household bleach solution which contain NaOCl as an active ingredient was diluted to 250cm3 ,
25cm3 of the diluted bleach solution is completely reacted with 10cm3 1M Kl(aq) and 10cm3 2M H2SO4.(Kl and H2SO4 is excess)
NaOCl + 2Kl +H2SO4 to form I2 +NaCl +H20 +K2SO4
The iodine given out is completely reacted with 15cm3 of 0.05M Na2S2O3.
l2+2NA2S2O3 to form 2Nal +Na2S4O6
calculate the molarity of NaOCl in the household bleach solution,
更新1:
10cm3 1M Kl(aq) and 10cm3 2M H2SO4.(Kl and H2SO4 is excess)呢D資料冇用?