At 25 °C and 775 Torr, carbon dioxide has a solubility of 0.0347 M in water. What is its solubility at 25 °C and 1670 Torr?
dont know where to start
At 25 °C and 775 Torr, carbon dioxide has a solubility of 0.0347 M in water. What is its solubility at 25 °C a?
2013-06-05 10:06 pm
回答 (3)
2013-06-06 4:10 pm
✔ 最佳答案
P = K * x where P is partial pressure K is Henry's constant and x is solubility775 torr = K L·torr/mol * 0.0.0347 mole / liter
K = 775 / 0.0347 = 22334 L·torr/mol
in the second solution we have
1670 = 22334 * x
x = 1670 / 22334
= 0.075 moles CO2 per liter of water
2015-10-02 12:13 am
S=Kh*P
Kh=0.0347/775
Kh=4.48*10^-5
S=4.48*10^-5*1670
S=0.075
Kh=0.0347/775
Kh=4.48*10^-5
S=4.48*10^-5*1670
S=0.075
收錄日期: 2021-05-01 19:46:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130605140626AAn9MyW