At 25 °C and 775 Torr, carbon dioxide has a solubility of 0.0347 M in water. What is its solubility at 25 °C a?

P = K * x where P is partial pressure K is Henry's constant and x is solubility

775 torr = K L·torr/mol * 0.0.0347 mole / liter

K = 775 / 0.0347 = 22334 L·torr/mol

in the second solution we have

1670 = 22334 * x

x = 1670 / 22334

= 0.075 moles CO2 per liter of water

S=Kh*P
Kh=0.0347/775
Kh=4.48*10^-5
S=4.48*10^-5*1670
S=0.075

What Is Solubility