一些電源轉換的物理問題

2013-06-04 1:39 pm
如果現在我有一鋰電池作供應
是12V 1.3Ah
經逆流變壓器的使用
把 DC 12V 轉成 AC 220V 使用

然後在另一端消耗電力
那邊插入的是一 AC Adapter
Input 是 220V 1.5A
Output 是 20V 3.25A 65W

假設逆流變壓器的工作效率是70%

請問另一端的AC Adapter 可以工作多長時間,直至到鋰電池完全沒有電力

同時請詳細列明計算步驟、使用的公式來顯示出如何得出答案

謝謝
更新1:

對不起 可否教一教小弟 「Current delivered by Li battery = 92.86/12 A = 7.738 A Time to run down the battery = 1.3/7.738 h = 1.68 h」 可否附上公式及詳細資料讓小弟學習及研究一下 謝謝

回答 (2)

2013-06-04 4:06 pm
✔ 最佳答案
Since output of ac adapter = 65 w (assume output current is at maximum of 3.25 A)
output from transformer = input to ac adapter = 65 w (assume the adapter is 100% efficiency)

Because the transformer is 70% efficient, hence power input to transformer by the Li battery = 65 x (100/70) w = 92.86 w

Current delivered by Li battery = 92.86/12 A = 7.738 A
Time to run down the battery = 1.3/7.738 h = 1.68 h

The actual time would be shorter than the calculated one, as the ac adapter msy not be 100% efficient.

Also, you need to be aware that the current delivered by the battery is quite large. This may exceed the current limit of the Li battery, causing the battery to become hot or even broken down.



2013-06-04 20:00:48 補充:
Your further questions:
Power = voltage x current
Since power delivered by the battery = 92.86 W, and voltage of battery = 12 v
current = power/voltage = 92.86/12 A

2013-06-04 20:05:45 補充:
Given capacity of battery = 1.3 A.h (ampere-hour)
But amphere-hour = current (in ampere) x time (in hours)
thus, 1.3 = 7.738 x time
time = 1.3/7.738 hours = 1.68 hours
2013-06-04 3:55 pm
逆流器效率七成,輸出有65wx0.7=45.5w,對電池消耗亦一樣,電流=45.5w/12v=3.79a,消耗時間=1.3a/3.79ax60m=20.58m(分鐘)。


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