The earth has a radius of 6380 km and turns around
once on its axis in 24h.
a) What is the radial acceleration of an object at the
earth's equator? Give your answer in m/s^2 and as a fraction
of g.
b) If the radial acceleration at the equator is greater than g,
objects will fly off the earth's surface and into space.
What would the period of the earth's rotation have to be for this to
occur?
ans:
a) 0.034 m/s^2
0.0034g
b) 1.4h
An object on the earth
2013-06-03 10:37 pm
回答 (1)
2013-06-04 3:36 am
✔ 最佳答案
(a) Radius of earth = 6380 km = 6.38 x 10^6 mAngular velocity of earth = 2.pi/(24x3600) s^-1 = 7.272 x 10^-5 s^-1
Radial acceleration = (6.38 x 10^6) x (7.272x10^-5)^2 m/s^2 = 0.0337 m/s^2 = 0.00337g (take g = 10 m/s^2)
(b) 10 = (6.38x10^6) x (2.pi/T)^2
where T is the new period of rotation
hence T = 5019 s = 1.39 h
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