Hi. I'm a 14 year old girl and I have a grade 8 assignment and I'm having trouble with it. Can you guys please help me out? Here is the problem:
The 1996 Problem
Using only the digits 1, 9, 9 and 6, find an expression equal to 1, then 2, then 3 and so on all the way up to 100. Each expression may contain only these four digits, so in any given expression, there will be one 1, two 9s, and one 6.
You may use the operations of addition, subtraction, multiplication and division, as well as juxtaposition (putting two numbers side by side, as in 99 or 61), exponents, square roots, factorials, and decimal points.
So. That's the question, and I'm having trouble with 91. Can you please help me? Thanks so much in advance! I look forward to rewarding you for your help with 10 points! :)
PLZ ANSWER A.S.A.P!!! 10 POINTS!!!?
2013-06-01 5:46 am
回答 (3)
2013-06-01 5:58 am
✔ 最佳答案
9^2 + sqaure root of 9 + 6 + 1Should equal 91 b/c 9^2=81. And Square root of 9 is 3. 3+6+1=10. 10+81=91
參考: My head.
2013-06-01 5:59 am
Let me think about it for a while. I don't suppose this would qualify?
91 * sqrt(sqrt(sqrt...infinite square roots...(9/6)...)))
91 * sqrt(sqrt(sqrt...infinite square roots...(9/6)...)))
2016-11-07 1:11 pm
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