f3 quadrilaterals
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f3 quadrilaterals
2013-05-26 7:13 pm
回答 (3)
2013-05-27 3:20 am
✔ 最佳答案
11(a)' . 'BD=DF , BC=CE (given)
. ' .CD//EF , EF=2CD (mid pt theorem)
' . 'AB//EF (given)
EF//CD (proved)
. ' .AB//CD
BD=DF (given)
. ' .AC=CF (mid pt theorem)
11(b)
' . 'BD=DF (given
AC=CF (proved in (a))
. ' .AB=2CD (mid pt theorem)
EF=2CD (proved in (a))
. ' .AB=EF
2013-06-04 21:51:41 補充：
有哂steps和reasons的啊~
多點溫書就可明白當中技巧~~
參考: , ME
2013-06-04 8:01 pm
*(angle:<)
∵<FAB=<AFE (alt. <s,AB//EF)
∵<ABE=<FEC (alt. <s,AB//EF)
∵BC=CE (given)
∴△ABC~=△FEC
a)AC=CF(corr. sides, △ABC~=△FEC)
b)AB-EF (corr. sides, △ABC~=△FEC)
∵<FAB=<AFE (alt. <s,AB//EF)
∵<ABE=<FEC (alt. <s,AB//EF)
∵BC=CE (given)
∴△ABC~=△FEC
a)AC=CF(corr. sides, △ABC~=△FEC)
b)AB-EF (corr. sides, △ABC~=△FEC)
參考: My own knowledge
2013-05-26 11:23 pm
Sol
BD=DE，BC=CE
CD//EF，EF=2CD
AB//EF
AB//CD
AB//CD，BD=DF
AC=CD……………(a)
AB=2CD
AB=EF…………….(b)
BD=DE，BC=CE
CD//EF，EF=2CD
AB//EF
AB//CD
AB//CD，BD=DF
AC=CD……………(a)
AB=2CD
AB=EF…………….(b)
收錄日期: 2021-04-20 13:52:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130526000051KK00077