chem 計equilibrium 20點急

2013-05-23 3:47 am
Please give full solution with detailed steps , thx!

1. The pH value of 1.862M propanoic acid is 2.3 . The equilibrium constant for the following equilibrium is Kc:

CH3CH2COOH + H20 -> <- (H3O^+) + (CH3CH2COO)^-

( a reversible reation )

i/ Calculate Kc for 1.862 M propanoic acid.
ii/ Calculate the pH value of when equal volumes of 3.724 M propanoic acid and
3.724 M sodium propanoate solution are mixed.

b/ The equilibrium constant of the following equilibrium is 1.51 x 10^-5 mol dm^-3

CH3CH2CH2COOH + H2O -> <- (CH3CH2CH2COO)^- + (H3O^-

i/ find the pH value of 0.8 M butanoic acid.
ii/ Equal volumes of 0.8 M butanoic acid and 0.1M sodium hydroxide solution are mixed together. Find the pH value of the resultant solution.

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