f.3 Maths 題,10分 考試用

At the beginning of the 2nd month, amount owed after repayment
= $36000 x [1 + (21%/12)] - $12400
= $24230

At the beginning of the 3nd month, amount owed after repayment
= $24230 x [1 + (21%/12)] - $12400
= $12254.03

At the beginning of the 3nd month, amount owed after repayment
= $12254.03 x [1 + (21%/12)] - $12400
= $68.48 > $0

Hence, he CANNOT repay all the amount owed in 3payments.
Amount still owed by him to the bank = $68.48