✔ 最佳答案
p = 30/100 = 0.3, α = 0.1, Z_α/2 = 1.645
p(1 - p) = 0.3 * 0.7 = 0.21, √[p(1 - p)/n] = 0.04583
So, the 90% confidence interval to estimate the population proportion is
p - Z_α/2 * √[p(1 - p)/n] < p_0 < p + Z_α/2 * √[p(1 - p)/n]
0.3 - 1.645 * 0.04583 < p_0 < 0.3 + 1.645 * 0.04583
0.2246 < p_0 < 0.3754