已知y(m^2-m)x^(m^2-3m+1)+m-3 是一次 函數,則m=3
我想知過程同點解.thz!
求解一次函數題目 !!!
2013-05-09 1:23 pm
回答 (2)
2013-05-09 4:06 pm
✔ 最佳答案
y = (m^2 - m)x^(m^2 - 3m + 1) + m - 3 是一次函數，則m^2 - 3m + 1 = 1 及 m^2 - m =/= 0
m^2 - 3m = 0 及 (m =/= 0 或 1)
(m = 0 或 m = 3) 及 (m =/= 0 或 1)
所以 m = 3
參考: knowledge
2013-05-09 4:12 pm
For the function to be of degree 1(一次 函數), the power of x must be 1.
The power of x^(m^2 - 3m + 1) must be equal to 1.
That is m^2 - 3m + 1 = 1
m^2 - 3m = 0
m(m - 3) = 0
m = 0 or 3.
m = 0 is rejected because the coefficient (m^2 - m) will then be 0.
so m = 3.
The power of x^(m^2 - 3m + 1) must be equal to 1.
That is m^2 - 3m + 1 = 1
m^2 - 3m = 0
m(m - 3) = 0
m = 0 or 3.
m = 0 is rejected because the coefficient (m^2 - m) will then be 0.
so m = 3.
收錄日期: 2021-04-25 22:38:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130509000051KK00029