求下題的餘式
(2x^3-3x^2+5x+6)除以(3-x)
要式!!!
THX
F4餘式定理(1條)(急急)
2013-05-07 5:26 am
回答 (2)
2013-05-07 5:35 am
✔ 最佳答案
(2x^3-3x^2+5x+6)=(3-x)Q(x)+R,where Q(x) is a polynomial in x and R is the remainder
Put x=3
R=2(3)^3-3(3)^2+5(3)+6
=54-27+15+6
=48//
2013-05-07 5:44 am
(2x^3-3x^2+5x+6)
_______________
(3-x)
(x)(2x^2-3x+5+6)
=_______________
3-x
(x)(2x^2-3x)+11x
=______________
3-x
(x^2)(2x-3+11)
=____________
3-x
(2x^3)+8x
=_________
3-x
(2x)(x^2+8x)
=__________
3-x
不肯定是否正確
I am F.3 only
I just try it
2013-05-06 21:46:40 補充：
原來是48.....
錯得很強勁
_______________
(3-x)
(x)(2x^2-3x+5+6)
=_______________
3-x
(x)(2x^2-3x)+11x
=______________
3-x
(x^2)(2x-3+11)
=____________
3-x
(2x^3)+8x
=_________
3-x
(2x)(x^2+8x)
=__________
3-x
不肯定是否正確
I am F.3 only
I just try it
2013-05-06 21:46:40 補充：
原來是48.....
錯得很強勁
收錄日期: 2021-04-13 19:27:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130506000051KK00308