F5 Maths question

2013-05-06 4:46 am
If ax + cy + bz = 0, cx + by + az = 0 and bx + ay + cz = 0, show that a3 + b3 + c3 = 3abc.

回答 (1)

2013-05-06 5:08 am
✔ 最佳答案
ax + cy + bz = 0...(1)
cx + by + az = 0...(2)
bx + ay + cz = 0...(3)

As (0,0,0) is one solution of the system. If there is another solution rather than (0,0,0), then there are infinite solutions of the system.

This implies that the determinant of the system is 0

| a c b |
| c b a | = 0
| b a c |

=> a^2 + b^2 + c^3 = 3abc


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