Find the equation of the tangent plane to the surface in the previous question at the point (x,y,z) where u =2 v = pi /6
this is the previous equation -4u^2 cosv i - 6 u^2 sinv j +12 u k
tangent plane
2013-05-02 9:47 pm
回答 (1)
2013-05-03 5:54 am
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130502000051KK00103