好心人Pls. help help幫幫忙牙? 麻煩有計算步驟
25cm^3 of potassium hydroxide solution is titrated against 0.1M sulphuric acid. The following table shows the titration results:
Burette readings(cm3) 1st 2nd 3rd 4th
Final reading 37.4 32.6 34.5 33.6
Initial reading 4.3 1.1 3.1 2.0
The molarity of potassium hydroxide solution is ?
化學 滴定
2013-04-29 4:21 pm
回答 (1)
2013-04-29 5:33 pm
✔ 最佳答案
2KOH + H2SO4 → K2SO4+ 2H2OVolume of 0.1 M H2SO4 used :
1st : 37.4 - 4.3 = 33.1 cm³
2nd : 32.6 - 1.3 = 31.3 cm³
3rd : 34.5 - 3.1 = 31.4 cm³
4th : 33.6 - 2.0 = 31.6 cm³
The 1st set of data is rejected due to large deviation.
Average volume of H2SO4 = (31.3 + 31.4 + 31.6) = 31.4 cm³
No. of moles of H2SO4 = 0.1 x (31.4/1000) = 0.00314 mol
No. of moles of KOH = 0.00314 x 2 = 0.00628 mol
Molarity of KOH = 0.00628 / (25/1000) = 0.251 M
參考: 賣女孩的火柴
收錄日期: 2021-04-13 19:26:58
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