中三三角比

2013-04-28 1:30 am
1.解三角比方程:

a)sinθ= sin62°/ √2

b)sinθ= 3sin40°/ 4

c)tanθ= 4tan70°-2tan30°

d)tanθ= tan17°tan23°

e)tanθ= 2tan30°/ tan50°

請列寫步驟!!謝謝!

回答 (1)

2013-04-28 3:44 am
✔ 最佳答案
設 0° ≤ θ ≤360°

若 0° ≤ θ ≤ 90°
只計算第一個答案便可。


a)
sinθ = sin62° / √2
sinθ = 0.6243
θ = 38.6° 或 θ = 180° -38.6°
θ = 38.6° 或 θ = 141.4°


b)
sinθ = 3sin40°/ 4
sinθ = 0.4821
θ = 28.8° 或 θ = 180°- 28.8°
θ = 28.8° 或 θ = 151.2°


c)
tanθ = 4tan70° - 2tan30°
tanθ = 9.835
θ = 84.2° 或 θ = 180° +84.2°
θ = 84.2° 或 θ = 264.2°


d)
tanθ = tan17° tan23°
tanθ = 0.1298
θ = 7.4° 或 θ = 180°+ 7.4°
θ = 7.4° 或 θ = 187.4°


e)
tanθ = 2tan30°/ tan50°
tanθ = 0.9689
θ = 44.1° 或 θ = 180°+ 44.1°
θ = 44.1° 或 θ = 224.1°

2013-04-27 20:24:10 補充:
更正後的 a)
sinθ = sin60° / √2
sinθ = 0.6124
θ = 37.8° 或 180° - 37.8°
θ = 37.8° 或 142.2°

2013-04-28 23:35:50 補充:
更正後的 a)
sinθ = sin60° / √2
sinθ = 0.6124
θ = 37.8° 或 180° - 37.8°
θ = 37.8° 或 142.2°
參考: 賣女孩的火柴, 賣女孩的火柴


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