若 (A/x+1) - (10/3x^2+x-2) ≡ (B/3x-2)
求常數 A 和 B 的值。
F4 Maths 有理函數(1)
2013-04-20 4:20 pm
回答 (1)
2013-04-20 5:07 pm
✔ 最佳答案
Put x=0LHS=A-(10/-2)=A+5
RHS=B/-2=(-1/2)B
A+5=(-1/2)B
-2A-10=B
2A+B= -10----------(1)
Put x=1
LHS= A/2 - (10/(3+1-2))=A/2 - 5
RHS= B/(3-2) = B
A/2 - 5 = B
A - 10 = 2B
A - 2B = 10-----------(2)
2(1)+(2): 4A+2B+A-2B = 2(-10)+10
5A=-10
A=-2 //
Put A=-2 into (1)
2(-2)+B= -10
B=-6 //
收錄日期: 2021-04-13 19:25:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130420000051KK00050