[(1+i) (4+i) ] / [(2-i) (3-i)]
Ans: [-1+ 8i]/ 10
2) [8-16i] / i [(2+6i)^2]
Ans: [1+2i] / 5
更新1:
I need the steps ahh
Imaginary Number Questions
2013-04-19 6:34 am
Simplify following in form of a+ bi [for 1 to ]
[(1+i) (4+i) ] / [(2-i) (3-i)]
Ans: [-1+ 8i]/ 10
2) [8-16i] / i [(2+6i)^2]
Ans: [1+2i] / 5
[(1+i) (4+i) ] / [(2-i) (3-i)]
Ans: [-1+ 8i]/ 10
2) [8-16i] / i [(2+6i)^2]
Ans: [1+2i] / 5
回答 (1)
2013-04-19 3:16 pm
✔ 最佳答案
Simplify following in form of a+ bi[(1+i) (4+i)] /[(2－i) (3-i)]
=(4+i+4i－1) /(6－2i－3i－1)
=(3+5i)/(5－5i)
=(3+5i)(5+5i)/[(5－5i)(5+5i)]
=(15+15i+25i－25)/(25+25)
=(－10+40i)/50
=(－2+8i)/10
2) (8－16i)/｛i [(2+6i)^2]｝
=(2－4i)/｛i [(1+3i)^2]｝
=(2－4i)/｛i [(1+6i－9]｝
=(2－4i)/[i (6i－8)]
=(2－4i)/(－6－8i)
=(1－2i)/(－3－4i)
=(1－2i)(－3+4i) /[(－3-4i)(－3+4i)]
=(－3+4i+6i+8)/(9+16)
=(5+10i)/25
=(1+2i)/5
收錄日期: 2021-04-30 17:36:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130418000051KK00368