The weight of an object varies inversely as the square of the distance from the center of the earth. At sea level (6400 km from the center of the earth), an astronaut weighs 100 lb. How far above the earth must the astronaut be in order to weigh 64 lb?
can i have the step and answer?
algerba
2013-04-11 6:56 pm
回答 (1)
2013-04-11 8:41 pm
✔ 最佳答案
Let d km be the distance from the centre of the earthand w lb be the weight.
thus, w = k / d^2 where k is a non-zero constant
100 = k / 6400^2
k = 4096000000
sub. k = 4096000000 and w = 64,
64 = 4096000000 / d^2
d^2 = 64000000
d = 8000
thus, the required distance = 8000 - 6400 = 1600 km
參考: knowledge
收錄日期: 2021-04-28 14:21:17
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