只需解第(a)題
我是這樣做的
用畢氏定理(2r)^2+(2r)^2=AC^2
但是請問怎樣拆成答案2√2r ?
http://i1233.photobucket.com/albums/ff400/rein1993/IMG_zps7ef7b208.jpg
數學-三角形/圓形圖像一問
2013-04-11 3:38 am
回答 (1)
2013-04-11 5:04 am
✔ 最佳答案
(a) AC^2 = (2r)^2 + (2r)^2 = 8r^2AC = √8r = 2√2r (因為2 = (√2)^2 = √(2^2))(b) 陰形面積= (2r)(2r)/2 - πr^2/2= 2r^2 - πr^2/2(c) 2r^2 - πr^2/2 = 24π4r^2 - πr^2 = 48πr = √[48π/(4 - π)] = 13.2540572
收錄日期: 2021-04-27 17:45:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130410000051KK00273