The scores of Ben, recorded on a random sample of eight games in this season were as below:
74,82,84,85,89,91,92,96
Q: Ben claims that his average score is better than his competitor, Mary. Mary has just reported that she has an average of 80 marks in all games she played in this season. At 95% confidence level, test, if Bens's claim is correct.
Normal Distribution..Help!
2013-04-08 5:16 am
回答 (2)
2013-04-09 6:18 am
✔ 最佳答案
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2013-04-10 9:52 pm
Ben's average score is: (74+82+84+85+89+91+92+96)/8
=693/8
=86.625
~86.6(correct to 1 decimal)
As 86.6>80, Ben's claim is correct.
=693/8
=86.625
~86.6(correct to 1 decimal)
As 86.6>80, Ben's claim is correct.
參考: myself
收錄日期: 2021-04-24 10:07:02
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130407000051KK00342