what is square root of -4?
回答 (19)
✔ 最佳答案
√-4 = √-1 x √4
=> i√4
i.e. ± 2i
:)>
2i
Because the square root of 4 is 2 and the square root of -1 is i
2 i
Easy to do on the calculator
But solved in my head
參考: Two years ago in grade 6 (now in year 8)
It has two square roots, being 2i and -2i.
we know that i^2 = - 1 , where 'i' is an imaginary no.
now,
- 4 = (i^2)*4 = (2i)^2
square root of -4 = + - 2i
+/-2[i], where i = root of -1
COME ON!!! you can't take a square root of a negative number, are you kidding me, lol!
Does not exist!!!
â- 4
= â4i^2
= +/- 2i Ans.
-4^1/2
-1*4^1/2. As we know -1^1/2=i (iota imaginary no.)
I(4^1/2)=i(2)=+-(2i). Note : ^1/2 represents square root and when take square we take both negative and postice value !
2i
for more information read theory of complex numbers
Hey!
Square root of -4?
The square root of a negative number does not exist in the real numbers.
But If you really want to be precise the answer is 2i. (Depending on the year you are in you really don't need that as an answer.)
The answer you really should put down is "No Solution"
Hope that had helped :)
參考: Myself: Doing advanced mathematics
收錄日期: 2021-04-17 02:18:33
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