F.4 physics (force and motion)

2013-04-04 7:40 am
1) 假設有個人係架加速緊既巴士上, 果個人隻腳同架巴士應該有一樣既acceleration,係咪姐係no relative motion? 咁點解佢地之間有friction?

2)objects moving at constant velocity係咪無net work done?

3)計PE果陣幾時要take reference level? 書d examples 都唔係次次有take

4)http://s1353.photobucket.com/user/s031026/media/1_zps60f19ddd.png.html is T1=T2? shouldnt that T2>T1 as the vertical component of T2 balances T1?

5)http://s1353.photobucket.com/user/s031026/media/P1020597_zps2dd80802.jpg.html how to calculate it?

6) http://s1353.photobucket.com/user/s031026/media/P1020595_zps62146ecf.jpg.html for (c), the equation of W=Fs is used, but i don't understand why the answer takes s=the distance travelled by the train instead of the displacement? According to the definition of work,s should be the displacement travelled by the train? Besides, what should be the displacement of the train if it travels from A to B?

million thanks!!!!!
更新1:

thanks everyone for helping!!! iamwhoiam: gd luck with yr DSE!! 4) the 2 circles are smooth pulleys and the whole system is at rest.

更新2:

5) When A exerts force on B (120N right?), B should also exert an equal but opposite force on A also. It turns out that A should remain at rest as the net force acting on it is 0.

更新3:

Besides, is it true that if two objects are packed closely, they should have same acceleration when a net force is acting on them regardless of their masses? Is there any explanation for it? once again thanks everyone!!

更新4:

4) What if I tie another weight to the other side so that it is in equilibrium? will T1 = T2? thanks!!

回答 (3)

2013-04-04 9:23 pm
✔ 最佳答案
1. There is no motion between an object and the surface when static frcition is acting, otherwise it becomes kinetic friction.

Static friction acts opposite to the direction that the object tends to move. When the bus moves forward, because of inertia, the man tends to remain behind. Hence, static friction acts in the forward direction.

2. An object moving at constant speed under balanced forces has no increase in kinetic energy. But it doesn't not necessarily mean that there is no work done.

An example is a force pulling an object to move at constant speed on a rough surface. The work done by the pulling force produces heat due to friction.

3. A reference level is just a convenient arbitrary level. Generally, it it the lowest level that can be attained by an object in question.

4. Your diagram is not clear enough. What does the large circle represent? Is the system in equilibrium?

5. You don't need to do any calculation. It is clearly 1:1 (oprion A). Object B is being pushed to move by object A. The two are in contact and hence possess the same acceleration.

6. In using the formula: W = F.s, the force F must be in the same direction as that of the displacement s.
In the track from A to B, F (the frictional force) changes its direction at the bottom of the slope, varies its direction continuously at the circular track, and finally at the level track. Therefore, you cannot simply use the displacement from A to B (i.e. a straight line joining A and B) in calculating the work done by friction.

Since friction is always in direction opposite to the motion (the velocity), the displacement s under such situation follows the actual path covered by the roller coaster.




2013-04-05 07:43:14 補充:
Your suppl questions:
4. If the two circles represent smooth pulleys, the system wouldn't be in equilibrium. The weight would fall.

2013-04-05 07:47:46 補充:
Your suppl question:
5. The 120N force is applied to A, NOT to B. The force that A exerts on B is smaller than 120N. The net force (i.e. 120N minus the force B exerts on A) gives an acceleration to A.

2013-04-05 07:49:30 補充:
see "opinion section" for answer to Q5

2013-04-05 07:53:20 補充:
Two objects linked together (that means they would not be separated physically) can be considered as a single object. Naturally, they have the same velocity and acceleration.

2013-04-05 07:57:03 補充:
A daily example is a MTR train. A train is composed of 10 individual train-cars linked together. Each train-car has the same acceleration and velocity. If not, you could imagine what would happen.
2013-04-04 8:59 am
i am busy preparing dse now, so i don't have time to ans all your question(and the reward is 5pt only--no offense), but i would still like to help you a bit.

1) i think you should think about why a person accelerates when the bus move, it's just because of friction! 1. the bus moves relative to the person, a friction f is exerted on the bus floor by the person (and is in a direction which is opposite to the motion of bus) 2. by newton's 3rd law, a force is exerted on people in oppoiste direction of f (which is in the same direction as the motion of bus) 3. the person moves together with the bus

a bit messy, hope u understand...

2)as net force=0>> no work done

3)i think it is not important as usually we find our ans by using increase/decrease in PE which is the same , no matter a reference point is considered or not

2013-04-04 01:03:27 補充:
1. the bus moves relative to the person
(because the person doesn't move at the beginning)
2013-04-04 8:28 am
1)由於 物體(人) 與 正在加速的物體在"同一個參考系統(System)"上,因此沒有相對 運動(Relative motion).若沒有相對運動的趨勢,則不會產生摩擦力(Friction).

2)於此時因為沒有淨力(Net force),根據公式 W = F x d ,也沒有作功(Work).

3)......

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